№8 — #8123

from itertools import *
k = 0
for w in product('0123456789ab', repeat=6):
    s = ''.join(w)
    ch = s.count('0') + s.count('2') + s.count('4') + s.count('6') + s.count('8') + s.count('a')
    nch = s.count('1') + s.count('3') + s.count('5') + s.count('7') + s.count('9') + s.count('b')
    if s[0] != '0' and s.count('b') == 1 and ch == nch:
        k += 1
print(k)